0=4.9t^2+10t+120

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Solution for 0=4.9t^2+10t+120 equation: 



0=4.9t^2+10t+120

We move all terms to the left:

0-(4.9t^2+10t+120)=0

We add all the numbers together, and all the variables

-(4.9t^2+10t+120)=0

We get rid of parentheses

-4.9t^2-10t-120=0

a = -4.9; b = -10; c = -120;
Δ = b2-4ac
Δ = -102-4·(-4.9)·(-120)
Δ = -2252
Delta is less than zero, so there is no solution for the equation

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